Add a better DFS solution
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@@ -1,24 +1,33 @@
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# Adjacency list
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first_graph = {
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1: [3, 20],
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1: [3, 20, 4, 5, 6],
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2: [20],
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3: [1, 20],
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20: [2, 3]
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20: [2, 3],
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4: [1],
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5: [1],
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6: [1]
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}
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# First exercise: go from 1, to 20, to 2
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first_graph[first_graph[1][1]][0]
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# pass visited by reference
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def depth_first_search(graph: dict, start, visited=set()):
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print(start)
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def depth_first_search(graph: dict, start, visited=set(), traversal=list()):
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if start in visited:
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return
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visited.add(start)
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traversal.append(start)
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if len(visited)==len(graph):
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return visited
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return
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for x in graph[start]:
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if x not in visited:
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visited.add(x)
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return depth_first_search(graph, x, visited)
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depth_first_search(graph, x, visited, traversal)
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depth_first_search(first_graph, 1)
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visited = set()
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traversal = list()
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depth_first_search(first_graph, 1, visited, traversal)
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print("Visited:", visited)
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print("Traversal:", traversal)
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