Add 2026.07.01 homework

notes-and-examples/2026.06.12/overview.md

@@ -1,7 +1,7 @@
 ## Outline
 
 - Write a red-black tree with rebalancing
-- Assignment: start on the red-black tree
+- Assignment: start on the red-black tree (moved to 2026.07.01)
     - Requirement: you must use the left- and right-rotation code in the previous assignment
     - You may change the code to fit the class
 - Next week: introduce graphs and graph algorithms

notes-and-examples/2026.06.12/red_black_tree.py

@@ -1,178 +0,0 @@
-class Node:
-    def __init__(self, value, left=None, right=None, parent=None):
-        self.value = value
-        self.left: Node | None = left
-        self.right: Node | None = right
-
-        # required to re-set the child later
-        self.parent: Node | None = parent
-
-class RedBlackTree:
-    def __init__(self):
-        self.root: Node | None = None
-
-    def insert(self, value):
-        # assumption: inserting the same value twice will
-        # insert nothing the second time
-
-        node = Node(value)
-        if self.root is None:
-            self.root = node
-            return
-
-        # insert like a normal binary search tree
-        prev: Node | None = None
-        current = self.root
-        while current:
-            if current.value == value:
-                return
-            prev = current
-            if current.value > value:
-                current = current.left
-            elif current.value < value:
-                current = current.right
-
-        if prev and prev.value > value:
-            prev.left = node
-        elif prev and prev.value < value:
-            prev.right = node
-
-    def delete(self, value, root=None, parent=None):
-        # does nothing if the value doesn't exist
-        if parent is None:
-            root = self.root
-            if root is None:
-                return
-
-        if root.value == value:
-            new_root: Node | None
-            if root.left is None:
-                new_root = root.right
-            elif root.right is None:
-                new_root = root.left
-            else:
-                # both left and right subtrees exist
-                # make left subtree root the tree root, and re-attach
-                # the right subtree
-                right_subtree_root = root.right
-                new_root = root.left
-
-                prev = None
-                current = new_root
-                while current:
-                    prev = current
-                    current = current.right
-                prev.right = right_subtree_root
-
-            if parent is None:
-                self.root = new_root
-            else:
-                if parent.value > root.value:
-                    parent.left = new_root
-                else:
-                    parent.right = new_root
-        elif root.value > value:
-            self.delete(value, root.left, root)
-        elif root.value < value:
-            self.delete(value, root.right, root)
-
-    def rebalance(self):
-        # this is what we'll be implementing
-        pass
-
-    def visualize(self) -> str:
-        # renders the tree top-down with the root on top and branches
-        # ( / and \ ) drawn down to each child. spacing is computed so that
-        # subtrees never overlap, no matter the shape of the tree.
-        if self.root is None:
-            return "<empty tree>"
-
-        # render() returns, for the subtree rooted at `node`:
-        #   lines  - the block of text drawing the subtree
-        #   width  - how many characters wide that block is
-        #   height - how many lines tall that block is
-        #   middle - the column where this node's value is centred (so the
-        #            caller knows where to attach its branch)
-        def render(node: Node) -> tuple[list[str], int, int, int]:
-            label = str(node.value)
-            label_width = len(label)
-
-            # leaf: just the value on a single line
-            if node.left is None and node.right is None:
-                return [label], label_width, 1, label_width // 2
-
-            # only a left child
-            if node.right is None:
-                lines, width, height, mid = render(node.left)
-                first = (mid + 1) * " " + (width - mid - 1) * "_" + label
-                second = mid * " " + "/" + (width - mid - 1 + label_width) * " "
-                shifted = [line + label_width * " " for line in lines]
-                return [first, second] + shifted, width + label_width, height + 2, width + label_width // 2
-
-            # only a right child
-            if node.left is None:
-                lines, width, height, mid = render(node.right)
-                first = label + mid * "_" + (width - mid) * " "
-                second = (label_width + mid) * " " + "\\" + (width - mid - 1) * " "
-                shifted = [label_width * " " + line for line in lines]
-                return [first, second] + shifted, width + label_width, height + 2, label_width // 2
-
-            # two children: render each side, then place this node between them
-            left_lines, left_w, left_h, left_mid = render(node.left)
-            right_lines, right_w, right_h, right_mid = render(node.right)
-            first = (
-                (left_mid + 1) * " "
-                + (left_w - left_mid - 1) * "_"
-                + label
-                + right_mid * "_"
-                + (right_w - right_mid) * " "
-            )
-            second = (
-                left_mid * " "
-                + "/"
-                + (left_w - left_mid - 1 + label_width + right_mid) * " "
-                + "\\"
-                + (right_w - right_mid - 1) * " "
-            )
-            # pad the shorter side so the two blocks line up row-for-row
-            if left_h < right_h:
-                left_lines += [left_w * " "] * (right_h - left_h)
-            elif right_h < left_h:
-                right_lines += [right_w * " "] * (left_h - right_h)
-            merged = [l + label_width * " " + r for l, r in zip(left_lines, right_lines)]
-            return (
-                [first, second] + merged,
-                left_w + right_w + label_width,
-                max(left_h, right_h) + 2,
-                left_w + label_width // 2,
-            )
-
-        lines, _, _, _ = render(self.root)
-        return "\n".join(lines)
-
-# Sample visualizations
-tree = RedBlackTree()
-tree.insert(20)
-tree.insert(10)
-tree.insert(5)
-tree.insert(30)
-tree.insert(40)
-print(tree.visualize())
-
-tree.delete(20)
-print(tree.visualize())
-
-tree.delete(40)
-tree.delete(5)
-print(tree.visualize())
-
-tree.delete(10)
-print(tree.visualize())
-
-tree.delete(30)
-print(tree.visualize())
-
-# attempt duplicate delete
-tree.delete(30)
-print(tree.visualize())
-

notes-and-examples/2026.07.01/overview.md

@@ -0,0 +1,41 @@
+## Outline
+
+- Review tree rotations and red-black trees
+- Properties of a red-black tree
+    - Top (root) node is black
+    - The children and parent of a red node are black
+    - Null nodes are colored black
+    - The path from any particular node to a null node must contain the
+      same number of black nodes
+- Dive into the steps for rebalancing a red-black tree
+
+Also see the accompanying whiteboard pictures.
+
+![Rotations](rotations.png)
+
+![Red-black trees](red-black-trees.png)
+
+## Assignment
+
+**Clarifications on the red-black tree example:**
+
+- In your assignment, you should first color a node _red_ when inserting it.
+    - Then, check for red-red violations (the second rule). Then, rebalance if necessary.
+- If the uncle of the inserted node (parent → parent → right child) is red,
+  you'll want to do two things:
+    - Color the parent, uncle, and grandparent in a way which preserves all the rules
+      (which ones are colored which, are an exercise left to you)
+    - _Recursively_ run the rebalancing algorithm on the grandparent
+- Otherwise, your task is to figure out the correct conditions in which
+  each of the rebalancing algorithms apply.
+
+Copy 2026.07.01/homework.py into your own [Git repository](https://gitea.bchen.dev/ethan/dsa-homework),
+with a new folder for the date. Implement the `rebalance_from_just_inserted`
+function.
+
+Don't change the test cases, but use them to inform how you implement your
+code. Try to pass all the test cases.
+
+Follow the instructions from last session (2026.06.12) to commit and push
+your changes to Gitea.
+

notes-and-examples/2026.07.01/red_black_tree.py

@@ -0,0 +1,412 @@
+class Node:
+    def __init__(self, value, left=None, right=None, parent=None, is_red=False):
+        self.value = value
+        self.left: Node | None = left
+        self.right: Node | None = right
+        self.is_red = is_red
+
+        # required to traverse the tree and perform various checks
+        self.parent: Node | None = parent
+
+class RedBlackTree:
+    def __init__(self):
+        self.root: Node | None = None
+
+    def insert(self, value):
+        # assumption: inserting the same value twice will
+        # insert nothing the second time
+
+        node = Node(value)
+        if self.root is None:
+            # the root is always black (Node defaults to black)
+            self.root = node
+            return
+
+        # insert like a normal binary search tree
+        prev: Node | None = None
+        current = self.root
+        while current:
+            if current.value == value:
+                return
+            prev = current
+            if current.value > value:
+                current = current.left
+            elif current.value < value:
+                current = current.right
+
+        # a newly inserted (non-root) node is always red, and it needs a
+        # parent pointer so rebalancing can walk back up toward the root
+        node.is_red = True
+        node.parent = prev
+        if prev and prev.value > value:
+            prev.left = node
+        elif prev and prev.value < value:
+            prev.right = node
+
+        self.rebalance_from_just_inserted(node)
+
+    def delete(self, value, root=None, parent=None):
+        # does nothing if the value doesn't exist
+        if parent is None:
+            root = self.root
+            if root is None:
+                return
+
+        if root.value == value:
+            new_root: Node | None
+            if root.left is None:
+                new_root = root.right
+            elif root.right is None:
+                new_root = root.left
+            else:
+                # both left and right subtrees exist
+                # make left subtree root the tree root, and re-attach
+                # the right subtree
+                right_subtree_root = root.right
+                new_root = root.left
+
+                prev = None
+                current = new_root
+                while current:
+                    prev = current
+                    current = current.right
+                prev.right = right_subtree_root
+
+            if parent is None:
+                self.root = new_root
+            else:
+                if parent.value > root.value:
+                    parent.left = new_root
+                else:
+                    parent.right = new_root
+        elif root.value > value:
+            self.delete(value, root.left, root)
+        elif root.value < value:
+            self.delete(value, root.right, root)
+
+    def rebalance_from_just_inserted(self, node: Node):
+        # This is what you'll be implementing.
+        #
+        # By the time this is called, `node` has already been inserted like a
+        # normal BST node, colored red, and had its `parent` pointer set (see
+        # insert()). Your job is to restore the red-black properties by
+        # rebalancing the subtree around `node`.
+        #
+        # Rebalancing is only needed when node.parent is red. Remember to keep
+        # the root black at the end.
+        pass
+
+    def visualize(self) -> str:
+        # renders the tree top-down with the root on top and branches
+        # ( / and \ ) drawn down to each child. spacing is computed so that
+        # subtrees never overlap, no matter the shape of the tree.
+        if self.root is None:
+            return "<empty tree>"
+
+        # render() returns, for the subtree rooted at `node`:
+        #   lines  - the block of text drawing the subtree
+        #   width  - how many characters wide that block is
+        #   height - how many lines tall that block is
+        #   middle - the column where this node's value is centred (so the
+        #            caller knows where to attach its branch)
+        def render(node: Node) -> tuple[list[str], int, int, int]:
+            # label shows the value plus its color: R (red) or B (black)
+            label = f"{node.value}{'R' if node.is_red else 'B'}"
+            label_width = len(label)
+
+            # leaf: just the value on a single line
+            if node.left is None and node.right is None:
+                return [label], label_width, 1, label_width // 2
+
+            # only a left child
+            if node.right is None:
+                lines, width, height, mid = render(node.left)
+                first = (mid + 1) * " " + (width - mid - 1) * "_" + label
+                second = mid * " " + "/" + (width - mid - 1 + label_width) * " "
+                shifted = [line + label_width * " " for line in lines]
+                return [first, second] + shifted, width + label_width, height + 2, width + label_width // 2
+
+            # only a right child
+            if node.left is None:
+                lines, width, height, mid = render(node.right)
+                first = label + mid * "_" + (width - mid) * " "
+                second = (label_width + mid) * " " + "\\" + (width - mid - 1) * " "
+                shifted = [label_width * " " + line for line in lines]
+                return [first, second] + shifted, width + label_width, height + 2, label_width // 2
+
+            # two children: render each side, then place this node between them
+            left_lines, left_w, left_h, left_mid = render(node.left)
+            right_lines, right_w, right_h, right_mid = render(node.right)
+            first = (
+                (left_mid + 1) * " "
+                + (left_w - left_mid - 1) * "_"
+                + label
+                + right_mid * "_"
+                + (right_w - right_mid) * " "
+            )
+            second = (
+                left_mid * " "
+                + "/"
+                + (left_w - left_mid - 1 + label_width + right_mid) * " "
+                + "\\"
+                + (right_w - right_mid - 1) * " "
+            )
+            # pad the shorter side so the two blocks line up row-for-row
+            if left_h < right_h:
+                left_lines += [left_w * " "] * (right_h - left_h)
+            elif right_h < left_h:
+                right_lines += [right_w * " "] * (left_h - right_h)
+            merged = [l + label_width * " " + r for l, r in zip(left_lines, right_lines)]
+            return (
+                [first, second] + merged,
+                left_w + right_w + label_width,
+                max(left_h, right_h) + 2,
+                left_w + label_width // 2,
+            )
+
+        lines, _, _, _ = render(self.root)
+        return "\n".join(lines)
+
+
+# =============== TEST CASES ===================
+#
+# These run automatically:   python red_black_tree.py
+#
+# Each case inserts ONE value into a hand-built red-black tree and checks the
+# result, printing the tree BEFORE, the ACTUAL tree after your rebalance, and
+# the EXPECTED tree. A case passes when the actual tree matches the expected
+# tree AND the result is still a valid red-black tree.
+#
+# HOW TO ADD YOUR OWN CASE:
+#   Append a Case(...) to the CASES list below with four fields:
+#       name     - short description
+#       before   - a function returning the tree BEFORE the insert (None = empty)
+#       insert   - the value to insert
+#       expected - a function returning the tree you expect AFTERWARD
+#   Build trees with node(value, "R" or "B", left=..., right=...). Any child
+#   you leave out is treated as a (black) nil leaf.
+
+from dataclasses import dataclass
+from typing import Callable
+
+
+def node(value, color, left=None, right=None):
+    """Build a Node with an explicit color ("R"/"B"), wiring parent pointers."""
+    n = Node(value, is_red=(color == "R"))
+    n.left = left
+    n.right = right
+    if left is not None:
+        left.parent = n
+    if right is not None:
+        right.parent = n
+    return n
+
+
+def tree(root):
+    """Wrap a root Node (or None) in a RedBlackTree."""
+    t = RedBlackTree()
+    t.root = root
+    return t
+
+
+@dataclass
+class Case:
+    name: str
+    before: Callable      # () -> Node | None
+    insert: int
+    expected: Callable    # () -> Node | None
+
+
+CASES = [
+    Case(
+        "Empty tree -> black root",
+        before=lambda: None,
+        insert=25,
+        expected=lambda: node(25, "B"),
+    ),
+    Case(
+        "Black parent -> new red child, no rebalancing",
+        before=lambda: node(25, "B"),
+        insert=15,
+        expected=lambda: node(25, "B", left=node(15, "R")),
+    ),
+    Case(
+        "Duplicate insert -> tree unchanged",
+        before=lambda: node(25, "B", left=node(15, "R")),
+        insert=15,
+        expected=lambda: node(25, "B", left=node(15, "R")),
+    ),
+    Case(
+        "Red uncle -> recolor (grandparent is the root)",
+        before=lambda: node(25, "B", left=node(15, "R"), right=node(35, "R")),
+        insert=10,
+        expected=lambda: node(
+            25, "B",
+            left=node(15, "B", left=node(10, "R")),
+            right=node(35, "B"),
+        ),
+    ),
+    Case(
+        "LL -> right-rotate the grandparent",
+        before=lambda: node(30, "B", left=node(20, "R")),
+        insert=10,
+        expected=lambda: node(20, "B", left=node(10, "R"), right=node(30, "R")),
+    ),
+    Case(
+        "RR -> left-rotate the grandparent",
+        before=lambda: node(30, "B", right=node(40, "R")),
+        insert=50,
+        expected=lambda: node(40, "B", left=node(30, "R"), right=node(50, "R")),
+    ),
+    Case(
+        "LR -> left-rotate parent, then right-rotate grandparent",
+        before=lambda: node(30, "B", left=node(20, "R")),
+        insert=25,
+        expected=lambda: node(25, "B", left=node(20, "R"), right=node(30, "R")),
+    ),
+    Case(
+        "RL -> right-rotate parent, then left-rotate grandparent",
+        before=lambda: node(30, "B", right=node(40, "R")),
+        insert=35,
+        expected=lambda: node(35, "B", left=node(30, "R"), right=node(40, "R")),
+    ),
+    Case(
+        "Cascade: recolor propagates up, then rotate near the root",
+        before=lambda: node(
+            11, "B",
+            left=node(
+                2, "R",
+                left=node(1, "B"),
+                right=node(7, "B", left=node(5, "R"), right=node(8, "R")),
+            ),
+            right=node(14, "B", right=node(15, "R")),
+        ),
+        insert=4,
+        expected=lambda: node(
+            7, "B",
+            left=node(
+                2, "R",
+                left=node(1, "B"),
+                right=node(5, "B", left=node(4, "R")),
+            ),
+            right=node(
+                11, "R",
+                left=node(8, "B"),
+                right=node(14, "B", right=node(15, "R")),
+            ),
+        ),
+    ),
+]
+
+
+def validate_rb(t):
+    """Return a list of red-black property violations ([] means valid)."""
+    problems = []
+    root = t.root
+    if root is None:
+        return problems
+    if root.is_red:
+        problems.append("root is red")
+    if root.parent is not None:
+        problems.append("root has a non-None parent pointer")
+
+    black_heights = set()
+    seen = set()
+
+    def check(n, low, high, black_count):
+        if n is None:
+            black_heights.add(black_count + 1)  # nil leaves count as black
+            return
+        if id(n) in seen:
+            # a proper tree never reaches the same node twice
+            problems.append(f"not a tree: node {n.value} reached twice (cycle or shared subtree)")
+            return
+        seen.add(id(n))
+        if low is not None and n.value <= low:
+            problems.append(f"BST order broken at {n.value}")
+        if high is not None and n.value >= high:
+            problems.append(f"BST order broken at {n.value}")
+        if n.is_red and ((n.left and n.left.is_red) or (n.right and n.right.is_red)):
+            problems.append(f"red node {n.value} has a red child")
+        if n.left is not None and n.left.parent is not n:
+            problems.append(f"broken parent pointer: left child {n.left.value} does not point back to {n.value}")
+        if n.right is not None and n.right.parent is not n:
+            problems.append(f"broken parent pointer: right child {n.right.value} does not point back to {n.value}")
+        nb = black_count + (0 if n.is_red else 1)
+        check(n.left, low, n.value, nb)
+        check(n.right, n.value, high, nb)
+
+    check(root, None, None, 0)
+    if len(black_heights) > 1:
+        problems.append(f"unequal black-heights on paths to nil: {sorted(black_heights)}")
+    return problems
+
+
+def _indent(text: str) -> str:
+    return "\n".join("    " + line for line in text.split("\n"))
+
+
+def run_tests():
+    passed = 0
+    for i, case in enumerate(CASES, 1):
+        print("=" * 64)
+        print(f"CASE {i}: {case.name}")
+        print("=" * 64)
+
+        t = tree(case.before())
+        print("BEFORE:")
+        print(_indent(t.visualize()))
+        print(f"\n  insert({case.insert})\n")
+
+        # Everything the student's code can affect is inside this guard, so a
+        # buggy rebalance (even one that builds a cyclic/broken tree) fails just
+        # this case instead of aborting the whole suite.
+        try:
+            t.insert(case.insert)
+            actual = t.visualize()
+            expected_tree = tree(case.expected())
+            expected = expected_tree.visualize()
+            violations = validate_rb(t)
+            expected_problems = validate_rb(expected_tree)
+        except RecursionError:
+            print("  RESULT: ERROR - hit maximum recursion depth.")
+            print("    Your rebalance likely created a cycle or otherwise broke the")
+            print("    tree structure (a child pointing back up at an ancestor).\n")
+            continue
+        except Exception as e:
+            print(f"  RESULT: ERROR - {type(e).__name__}: {e}\n")
+            continue
+
+        # Guard the author (you) against a typo when adding a new case: the
+        # 'expected' tree should itself be a valid red-black tree.
+        if expected_problems:
+            print("  RESULT: BAD TEST - the 'expected' tree is not a valid red-black tree:")
+            for p in expected_problems:
+                print(f"    - {p}")
+            print()
+            continue
+
+        print("ACTUAL (what your code produced):")
+        print(_indent(actual))
+        print("\nEXPECTED:")
+        print(_indent(expected))
+        print()
+
+        if actual == expected and not violations:
+            print("  RESULT: PASS")
+            passed += 1
+        else:
+            print("  RESULT: FAIL")
+            if actual != expected:
+                print("    - actual tree does not match the expected tree")
+            for v in violations:
+                print(f"    - red-black property broken: {v}")
+        print()
+
+    print("=" * 64)
+    print(f"{passed}/{len(CASES)} cases passed")
+    print("=" * 64)
+
+
+if __name__ == "__main__":
+    run_tests()